# college

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1. Solve.
2x+3y+4z=2
5x-2y+3z=0
x-5y-2z=-4

A.
(3, 4, 2)

B.
(-2 ,1, 2)

C.
(2, 2, -2)

D.
(1, 1, -2)

• college -- Math -

The school subject is math, not college.

• college -

You could either substitute the 4 sets of values into one equation or start solving:

1. 2x+3y+4z=2
2. 5x-2y+3z=0
3. x-5y-2z=-4

Equ 1 x 2
4x+6y+8z=4

Equ 2 x 3
15x-6y+9z=0

from by inspection z must be opposite sign to x and x equals z so B) and C) are possible answers.

You could either continue solving the equations or substitute the two sets in say equation 1.

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