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solve the system -32+3z=4 (x-2y) 4 (x-2y-z)= -36 -2 (2x+y)+2z=-12.

  • math -

    Is it ???
    -32+3z=4(x-2y) then 4x-8y-3z = -32 (1)
    4(x-2y-z)= -36 then 4x-8y+2z = -36 (2)
    -2(2x+y)+2z=-12 then -4x-2y+2z = -12 (3)

    (1) - (2) ---> z = 4
    (2) + (3) ----> -10y - 2z = -48
    -10y - 8 = -48
    y = 4

    back in (1)
    4x - 32 - 12 = -32
    x = 3

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