# math ln

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how do i solve for t:

-.50=1-e^-(t/125)^5

i got this far:

ln(.5)=5ln(-t/125)

t=?

• math ln -

5 e^-(t/5^2) = 1.5
e^-(t/125) = .3
e^(t/125) = 1/.3 = 3.3333
t/125 = ln 3.3333
t = 150.5

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