can someone check the first one and help me with the last two
find the values of s in the interval [0,pi/2] that make the statements true.
1. sin s = 0.75438373
i got 0.8547148
2. cos s = 0.74241049
is it .83666126??
3. cot s = 5.6394377
:)
1. yes (with s in radians)
2. no. The answer is 0.734135 radians
3. tan s = 0.1773226
s = 0.1754984
thankyou very very much:)
can you please help me on one of my other questions too...
To find the values of s in the given interval that make the statements true, we can use inverse trigonometric functions. Here's how you can find the solutions for each problem:
1. sin s = 0.75438373
To find the value of s, you can use the inverse sine function (also known as arcsin). Here's the step-by-step process:
- Subtract 0.75438373 from both sides: sin s - 0.75438373 = 0
- Use the inverse sine function to find s: s = arcsin(0.75438373)
- Calculate the value using a calculator or math software: s ≈ 0.8547148
So, you are correct. The value of s that makes sin s = 0.75438373 in the interval [0, pi/2] is approximately 0.8547148.
2. cos s = 0.74241049
To find the value of s, you can use the inverse cosine function (also known as arccos). Here's the step-by-step process:
- Subtract 0.74241049 from both sides: cos s - 0.74241049 = 0
- Use the inverse cosine function to find s: s = arccos(0.74241049)
- Calculate the value using a calculator or math software: s ≈ 0.83666126
So, you are correct. The value of s that makes cos s = 0.74241049 in the interval [0, pi/2] is approximately 0.83666126.
3. cot s = 5.6394377
To find the value of s, you can use the inverse cotangent function (also known as arccot). Here's the step-by-step process:
- Take the reciprocal of both sides: cot s = 1/5.6394377
- Use the inverse cotangent function to find s: s = arccot(1/5.6394377)
- Calculate the value using a calculator or math software: s ≈ 0.17527364
So, the value of s that makes cot s = 5.6394377 in the interval [0, pi/2] is approximately 0.17527364.
I hope this helps! Let me know if you have any further questions.