explain why (x + y)2= x2 + y2
If you are telling me that
(x+y)^2 = x^2 + y^2
That is not true
(x+y)^2 = x^2 + 2 x y + y^2
as you can see by multiplying
(x+y)(x+y) = x(x+y) + y(x+y) =x^2 + xy + xy + y^2
Now if you mean
2 (x + y) = 2 x + 2 y
that is simply the distributive property of multipication.
solc for v
[\sqrt;[6v-2]]=[\sqrt;[9v-8]]
To understand why (x + y)2 equals x2 + y2, let's break down both sides of the equation.
Starting with the left side:
(x + y)2
This is the expression for squaring the sum of x and y. To evaluate this, we apply the distributive property, which states that (a + b)2 = a2 + 2ab + b2.
Using this formula, we can rewrite the left side accordingly:
(x + y)2 = x2 + 2xy + y2
Now, comparing this result to the right side of the equation (x2 + y2), we can see that it is not the same as our result for the left side. Therefore, the statement (x + y)2 = x2 + y2 is incorrect.
However, there is a different property called the FOIL method that relates to squaring binomials. The FOIL method states that (a + b)2 equals a2 + 2ab + b2, similar to what we derived earlier.
So, if the equation was (x + y)(x + y) instead of (x + y)2, it would indeed simplify to x2 + 2xy + y2, which is equal to (x + y)2.
In summary, the equation (x + y)2 = x2 + y2 is incorrect, but the equation (x + y)(x + y) = x2 + 2xy + y2 is valid.