# Physics

posted by .

After 35 minutes of jogging, at the 9-km point in a total 10-km race, jogger 1 is behind the leader and moving at the same speed. What would have to be your accelearation in order to catch up to the finish line? Assuming the leader maintains a constant speed the rest of the race.

• Physics -

1 what behind the leader? 1 km? I will assume so. After 35 minutes, runner 1 would then have 1 km to go and runner 2 would have 2 km to go. The race will be over in 1 km/(9 km/35 min) = 35/9 = 3.89 minutes. Runner 2 must have an average speed over the last 2 km of
2km/3.59 min = 0.557 km/min to catch up. He started the "finishing kick" at a speed of 8 km/35 min = 0.229 km/min and will have to end it at 0.656 km/min. Such a speed is not humanly possible.

I will leave you to compute the required acceleration. (A 0.427 km/min increase in speed in 3.89 minutes)

## Similar Questions

1. ### Physics

After 35 minutes of jogging, at the 9-km point in a total 10-km race, jogger A is behind the leader and moving at the same speed. What would have to be your accelearation in order to catch up to the finish line?
2. ### Physics

After 35 minutes of jogging, at the 9-km point in a total 10-km race, jogger A is behind the leader and moving at the same speed. What would have to be your accelearation in order to catch up to the finish line?
3. ### Physics

Sorry for rewording it wrong. After 35 minutes of jogging, at the 9-km point in a total 10-km race, jogger A is behind the leader and moving at the same speed. What would have to be Jogger A's accelearation in order to catch up to …
4. ### physics

need help with this physics questions a jogger runs with a velocity of 6km/h 25 degrees north west for 35 minutes and then changes direction , jogging for 20 minutes at 4.5km/h 65 degrees east of north. using a vector diagram determine …
5. ### algebra

A jogger leaves home and runs at a constant speed of 4 miles per hour. Nine minutes later, a bicyclist follows along the same route at a constant speed of 15 miles per hour. Find the bicyclist's travel time needed to catch the jogger.
6. ### Physics

"A jogger runs with a velocity of 6.0 km/h [25° N of W] for 35 min and then changes direction, jogging for 20 min at 4.5 km/h [65° E of N]. Using a vector diagram, determine the jogger's total displacement and his average velocity …
7. ### physics

After 35 minutes of running, at the 8-{\rm km} point in a 9-{\rm km} race, you find yourself 200m behind the leader and moving at the same speed. What should your acceleration be if you are to catch up by the finish line?
8. ### physics

After 35 minutes of running, at the 8-{\rm km} point in a 9-{\rm km} race, you find yourself 200m behind the leader and moving at the same speed. What should your acceleration be if you are to catch up by the finish line?
9. ### Physics

A jogger starting morning run accelerates from a stand still to their jogging pace of 8km/hr. They reach a speed of 8km/hr 5 seconds after starting. How long does it take the jogger to reach the end of their 20m driveway?