Physics

posted by .

After 35 minutes of jogging, at the 9-km point in a total 10-km race, jogger 1 is behind the leader and moving at the same speed. What would have to be your accelearation in order to catch up to the finish line? Assuming the leader maintains a constant speed the rest of the race.

Is the answer 3.7

  • Physics -

    1 what behind the leader? 1 km? I will assume so. After 35 minutes, runner 1 would then have 1 km to go and runner 2 would have 2 km to go. The race will be over in 1 km/(9 km/35 min) = 35/9 = 3.89 minutes. Runner 2 must have an average speed over the last 2 km of
    2km/3.59 min = 0.557 km/min to catch up. He started the "finishing kick" at a speed of 8 km/35 min = 0.229 km/min and will have to end it at 0.656 km/min. Such a speed is not humanly possible.

    I will leave you to compute the required acceleration. (A 0.427 km/min increase in speed in 3.89 minutes)

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Physics

    After 35 minutes of jogging, at the 9-km point in a total 10-km race, jogger A is behind the leader and moving at the same speed. What would have to be your accelearation in order to catch up to the finish line?
  2. Physics

    After 35 minutes of jogging, at the 9-km point in a total 10-km race, jogger A is behind the leader and moving at the same speed. What would have to be your accelearation in order to catch up to the finish line?
  3. Physics

    Sorry for rewording it wrong. After 35 minutes of jogging, at the 9-km point in a total 10-km race, jogger A is behind the leader and moving at the same speed. What would have to be Jogger A's accelearation in order to catch up to …
  4. physics

    need help with this physics questions a jogger runs with a velocity of 6km/h 25 degrees north west for 35 minutes and then changes direction , jogging for 20 minutes at 4.5km/h 65 degrees east of north. using a vector diagram determine …
  5. algebra

    A jogger leaves home and runs at a constant speed of 4 miles per hour. Nine minutes later, a bicyclist follows along the same route at a constant speed of 15 miles per hour. Find the bicyclist's travel time needed to catch the jogger.
  6. Physics

    "A jogger runs with a velocity of 6.0 km/h [25° N of W] for 35 min and then changes direction, jogging for 20 min at 4.5 km/h [65° E of N]. Using a vector diagram, determine the jogger's total displacement and his average velocity …
  7. physics

    After 35 minutes of running, at the 8-{\rm km} point in a 9-{\rm km} race, you find yourself 200m behind the leader and moving at the same speed. What should your acceleration be if you are to catch up by the finish line?
  8. physics

    After 35 minutes of running, at the 8-{\rm km} point in a 9-{\rm km} race, you find yourself 200m behind the leader and moving at the same speed. What should your acceleration be if you are to catch up by the finish line?
  9. Physics

    A jogger starting morning run accelerates from a stand still to their jogging pace of 8km/hr. They reach a speed of 8km/hr 5 seconds after starting. How long does it take the jogger to reach the end of their 20m driveway?
  10. Science - Please Check my Answer 2

    My problem: One runner in a relay race has a 1.50 s lead and is running at a constant speed of 3.25 m/s. The runner has 30.0 m to run before reaching the end of the track. A second runner moves in the same direction as the leader. …

More Similar Questions