can anyone help me with my math please?
Please post the problem that's giving you trouble and explain what you don't understand. Someone will be glad to help you.
I am having trouble setting up this equation. Can you assit me ?
[CUBERT(2x + 9)]=3
Cube both sides.
Solve for x.
Would cube mean mutiplu by 3?
By the way thank you dr bob for all of your help. I really appreciate it.
No, multiply by itself twice, not by three. Cube means to the third power.
Ok thanks. also do you know how to solve this ??
y= 2[SQRT(x - 1)]
This is what I am being asked
Give the domain (that is, possible values of x):
To amplify a little.
3^2 = 3*3 = 9
3^3 = 3*3*3 = 27
3^4 = 3*3*3*3 = ?? you get the idea.
Now, sqrt 9 = 3
cube rt 27 = 3
One more:
sqrt(x+2)^2=x+2
OK?
Thank you. IS this the problem I just sumbittted to you?? and if so how do I get to that??
Notice that when you square the square root of something, you just move the something out of the square root.
sqrt (x+2)^2 = x+2
same for cubing a cube rt.
cube rt (x+3)^3 = x+3
As for the y = 2*sqrt(x-1), do it the same way by squaring both sides, then factor. At least that's what I would do. Damon is the expert with this, not I.