Find dy/dx & d^2y/dx^2 y^2 - x^2 = 2 is the answer dy/dx=x/y; d^2y/dx^2= y^2-x^2/y^2
dy/dx = 2x/(2y) = x/y y'' = (y(1) - x(y'))/y^2 = (y - x(x/y))/y^2 = (y^2 - x^2)/y^3 you had y^2 at the bottom of your y'' did you notice that there was a y in the denominator of your top?
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