# Calculus

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Find dy/dx & d^2y/dx^2

y^2 - x^2 = 2

y^2-x^2/y^2

• Calculus -

2y(dy/dx) - 2x = 0
dy/dx = 2x/(2y) = x/y

y'' = (y(1) - x(y'))/y^2
= (y - x(x/y))/y^2
= (y^2 - x^2)/y^3

did you notice that there was a y in the denominator of your top?

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