posted by Bobby .
How many mL of 3.84 M HCL are required to consume 4.12g of Zinc in the following reaction?
Zn(s) + 2HCL(aq)----> ZnCl2(aq) + H2(g)
A method to work all stoichiometry problems.
1. Write the equation and balance it. Your's looks ok.
2. Convert what you are given into mols. In this case, mols Zn = grams/atomic mass.
3. Using the coefficients in the balanced equation, convert mols Zn to mols HCl.
4. Now that you have mols HCl, remember mols = M x L. You have mols and M, calculate L and convert to mL.
Post your work if you get stuck.
Your Steps made everything clear. Thank you so much :D