calculus

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y=5/x-3
find the zeros,relative min and max.the max and min
find the intervals on which yis positive or negative. on which y is decreasing.intervals y concave up or down.points of inflections

  • calculus -

    I bet you mean
    y = 5/(x-3) ????
    if so then
    approches zero at - infinity and + infinity
    undefined at x = 3
    negative between x = -oo and x = 3
    positive between x = 3 and x = +oo
    decreasing for all x except exactly as x = 3
    In other words goes down from 0 to -oo as x goes from -oo to 3
    then goes down from +oo to 0 as x goes from 3 to +oo

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