physics!-concervation of energy equations
posted by gaby .
2. a 755N diver drops from a board 10.0 m above the water's surface. Find the divers speed 5.00 m above the water's surface. then find the diver's speed just before striking the water.
3. if the diver in item 2 leaves the board with an initial upward speed of 2.00 m/s find the divers speed when striking the water.
i don't know how to start these two at all...i don't need the answer i just need the formulas that i use for it...i don't understand which ones to use.. plz help
you can use:
(vf)^2 = (v0)^ + 2as
where vf is "final velocity"
v0 is "initial velocity"
a is acceleration
and s is distance
is the initial velocity squared? it has an ^ ???
yes, if the initial velocity is squred
wait...if this is conservation of energy, better to use:
convert the potential energy into kinetic energy! (sorry).
potential energy is mgh, and kinetic enery is (1/2)m*v^2
lol wat do i do with that...do i put it equal to eachother
So, it depends on what you're currently studying. If you're studying equations of motion, then use my first suggestion, but if you're studying conservation of energy, use mgh = (1/2)m*v^2.
The m's cancel out:
So, gh = v^2/2. You can solve for v, the velocity, by setting h, the height, first to 5, and then to 10.
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