# physics!-concervation of energy equations

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2. a 755N diver drops from a board 10.0 m above the water's surface. Find the divers speed 5.00 m above the water's surface. then find the diver's speed just before striking the water.

3. if the diver in item 2 leaves the board with an initial upward speed of 2.00 m/s find the divers speed when striking the water.

i don't know how to start these two at all...i don't need the answer i just need the formulas that i use for it...i don't understand which ones to use.. plz help

• physics!-concervation of energy equations -

you can use:

(vf)^2 = (v0)^ + 2as

where vf is "final velocity"
v0 is "initial velocity"

a is acceleration
and s is distance

• physics!-concervation of energy equations -

is the initial velocity squared? it has an ^ ???

• physics!-concervation of energy equations -

yes, if the initial velocity is squred

• physics!-concervation of energy equations -

wait...if this is conservation of energy, better to use:

convert the potential energy into kinetic energy! (sorry).

potential energy is mgh, and kinetic enery is (1/2)m*v^2

• physics!-concervation of energy equations -

lol wat do i do with that...do i put it equal to eachother

• physics!-concervation of energy equations -

So, it depends on what you're currently studying. If you're studying equations of motion, then use my first suggestion, but if you're studying conservation of energy, use mgh = (1/2)m*v^2.

The m's cancel out:
So, gh = v^2/2. You can solve for v, the velocity, by setting h, the height, first to 5, and then to 10.

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Can someone help break this down.. Please tell me if what I identified is so far correct. Also what equations should I use?

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