posted by Daniel .
find solution to differential equation given the initial conditions DQ/dt=Q/5
Q= 50 when t= 0
i don't understand this one because of the division sign.
dQ/Q = dt/5
ln Q = t/5 + C
Q = C' exp (t/5)
C and C' are arbitiry constants that you can determine from the initial condition
Q = 50 exp (t/5)