Algebra check

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Convert to Logarithmic equations.

10. 4^-3 =1/64 I have the answer as log4 1/64 =-3

11. 144^1/2 =12 I have the answer as
log 144^12 =1/2

Are these answers right?

  • Algebra check -

    I must admit I'm not sure what you are doing but if I converted
    4^-3 = 1/64 to a log equation, I would write
    -3*log 4 = log(1/64).
    I don't know what your answer means as
    log4 1/64 = -3 since the 1/64 is just dangling out there by itself with nothing to tell me what you want to do with it.

    and for 144^1/2 = 12 I would write
    1/2*log 144 = log 12

    By the way, when you post problems, be careful that the NUMBER of the problem doesn't run into the problem. For example, the first problem I kept reading as 10.4^-3 = 1/64

  • Algebra check -

    Thanks.

  • Algebra check DrBob222 -

    I have a question the formula that I used was b^y=x means that logbx=y
    is this the correct formula?
    so using that formula I got the following.
    4^-3 =1/64 I have the answer as log4 1/64 =-3

    144^1/2 =12 I have the answer as
    log 144^12 =1/2

  • Algebra check DrBob222 -

    yes, you are right

    if by = x then logbx = y

    that is the basic definition of a logarithm

  • Algebra check Reiny -

    So then are these answers right?
    10.) 4^-3 =1/64 I have the answer as log4 1/64 =-3

    11.) 144^1/2 =12 I have the answer as
    log 144^12 =1/2

  • Algebra check Reiny -

    I don't like the way you wrote it as
    log 144^12 =1/2
    the ^ we use as an exponent sign, there is no exponent involved
    should have been

    log144 12 = 1/2

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