AP chemistry
posted by kuljit .
A typical electric air conditioner rated at 1.00 * 10^4 Btu/h (1 Btu = amount of energy required to raise the temperature of 1 lb of water by 1F). How much water must be evaporated each hour to dissipate as much heat as a typical electric air conditioner?

I don't work in BTU (or BTU/hr) but I looked on the Internet and found that the heat of vaporization of water = 970 BTU/lb.
Therefore, mass water (lb) x heat vap = 1 x 10^4 BTU/hr
mass water * 970 BTU/lb = 1 x 10^4 BTU
mass water = 1 x 10^4/970 = ??
Check my thinking. Check my work. 
easy