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chemistry

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A voltaic cell at 25oC consists of Mn/Mn2+ and Cd/Cd2+ half-cells with the initial concentrations [Mn2+] = 0.100 M and [Cd2+] = 0.0100 M. Use the Nernst equation to calculate E for this cell.
Cd+2(aq) + 2e- = Cd(s) . . . . . . Eo = -0.40 V

Mn+2(aq) + 2e- = Mn(s) . . . . . . . Eo = -1.18 V

  • chemistry -

    The overall reaction is:
    Mn(s) + Cd^2+(aq) --> Mn^2+(aq) + Cd(s)
    (Mn is higher on the activity series than Cd)
    Eo(cell) = Eo(Cd)- Eo(Mn) with 1M solutions at 298K
    Eo(cell) = -40v - (-1.18v) = 0.78v
    With the given concentrations,
    E(cell) = Eo(cell) - (0.059/n)(logQ),
    where Q = [Mn^2] / [Cd^2+], and
    n = 2
    Substitute and solve for E(cell) in the Nernst Equation above.

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