chemistry

posted by .

A voltaic cell at 25oC consists of Mn/Mn2+ and Cd/Cd2+ half-cells with the initial concentrations [Mn2+] = 0.100 M and [Cd2+] = 0.0100 M. Use the Nernst equation to calculate E for this cell.
Cd+2(aq) + 2e- = Cd(s) . . . . . . Eo = -0.40 V

Mn+2(aq) + 2e- = Mn(s) . . . . . . . Eo = -1.18 V

  • chemistry -

    The overall reaction is:
    Mn(s) + Cd^2+(aq) --> Mn^2+(aq) + Cd(s)
    (Mn is higher on the activity series than Cd)
    Eo(cell) = Eo(Cd)- Eo(Mn) with 1M solutions at 298K
    Eo(cell) = -40v - (-1.18v) = 0.78v
    With the given concentrations,
    E(cell) = Eo(cell) - (0.059/n)(logQ),
    where Q = [Mn^2] / [Cd^2+], and
    n = 2
    Substitute and solve for E(cell) in the Nernst Equation above.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. chemistry

    Could I get some help with these please? Thanks Calculate the electrical potential (V). Ag/1M Ag+1// 1M Fe+3/Fe Ag2+( aq ) + e – Ag+( aq ) 1.98 Fe3+( aq ) + 3e – Fe(s) –0.04 2. A voltaic cell is reconstructed used electrodes
  2. Any chemistry lovers?

    A voltaic cell consists of Mn/Mn2+ and Cd/Cd2+ half-cells with the following initial concentrations: [Mn2+] = 0.090 M; [Cd2+] = 0.060 M. A)What is the intital Ecell?
  3. Chemistry

    A voltaic cell consists of a Pb /Pb^2+ half-cell and a Cu/Cu^2 half-cell at 298K. The initial concentrations of Pb^2+ and Cu^2 are 5.20×10−2 M and 1.40 M, respectively.
  4. Chemistry

    I'm having trouble with the following question, any help would be greatly appreciated. A voltaic cell consists of a Zn/Zn^2+ half-cell and a Ni/Ni^2+ half-cell at 25 C . The initial concentrations of Ni^2+ and Zn^2+ are 1.30 M and …
  5. chemistry

    A voltaic cell consists of an Mn/Mn2+ half-cell and a Pb/Pb2+ half-cell. Calculate [Pb2+] when [Mn2+] is 2.3 M and Ecell = 0.49 V.
  6. Chemistry

    A 50.0 mL sample containing Cd2 and Mn2 was treated with 49.1 mL of 0.0700 M EDTA. Titration of the excess unreacted EDTA required 17.5 mL of 0.0300 M Ca2 . The Cd2 was displaced from EDTA by the addition of an excess of CN–. Titration …
  7. Chemistry

    A voltaic cell consists of a Pb/Pb2+ half-cell and a Cu/Cu2+ half-cell at 25 C. The initial concentrations of Pb+2 and Cu+2 are 0.0500 M and 1.50 M, respectively. A. What is the initial cell potential?
  8. chemistry

    Calculate the pH for the hydrogen half-cell of the following voltaic cell if the observed cell voltage is 1.00 V. Mn|Mn2+(1.00 M)||H+(pH =?
  9. Chemistry

    A voltaic cell consists of an Mn/Mn2+ half-cell and a Pb/Pb2+ half-cell. Calculate [Pb2+] when [Mn2+] is 2.1 M and Ecell = 0.13 V.
  10. Chemistry

    What initial concentration of Cd2+ is required to result in a cell potential of 0.200 V in a voltaic cell constructed by connecting a nickel electrode that is dipped into 1.00 M NiSO4 solution to a cadmium electrode that is dipped …

More Similar Questions