In triangle ABC, angle C is congruent to angle A, line BC=2x-5, line AB=x+5 and line AC=x+10. Find x.
The problem didn't have a triangle drawn so i drew it myself. I tried many equations but when i substitute it it didn't work.
You stated that angle C = angle A, so
BC = AB
then 2x-5 = x+5
x = 10
To find x in triangle ABC, we can start by using the fact that angle C is congruent to angle A. This implies that the corresponding sides opposite these angles are also congruent.
Using this information, we can set up the following equation based on the side lengths:
BC = AB
From the given information, we have:
BC = 2x - 5
AB = x + 5
Setting these two expressions equal to each other, we get:
2x - 5 = x + 5
Next, we can solve this equation for x. To do so, we can start by isolating the variable on one side of the equation.
Subtracting x and adding 5 to both sides, we have:
2x - x = 5 + 5
x = 10
Therefore, x = 10.