Algebra
posted by Celina .
Here's another problem I'm having a little trouble with:
A piece of string is 40 cm long. It is cut into three pieces. The longest piece is 3 times as long as the middlesized piece, and the shortest piece is 23 cm shorter than the longest piece. Find the lengths of the three pieces.
What could be an equation I could write?
Thank you so much!

Algebra 
Damon
call the middle size m
then the long piece is 3 m
and the short piece is 3m23
so
(3m23) + m + 3m = 40
7 m 23 = 40
solve for m 
Algebra 
Celina
Thank you very much!

Algebra 
Shika
7m  23 =40
+ 23 +23
then 7m=63
then you divide 63 by 7 it equal 9
so the ans. is m=9 :) 
Algebra 
Reiny
How about:
let the shortest piece be x cm
<the shortest piece is 23 cm shorter than the longest piece> or
the longest piece is 23 more than the shortest piece,
so longest = x+23
<The longest piece is 3 times as long as the middlesized piece> or
the middle piece is 1/3 of the longest piece,
so middle piece = 1/3(x+23)
then x + (x+23) + 1/3(x+23) = 40
(I get x=4, for the shortest piece of 4 cm) 
Algebra 
Celina
Thanks!

Algebra 
Rachael
whats the answer?
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