Given the chemical reaction:
N2+3H2--->2NH3
If 20 molecules of nitrogen react with 30 molecules of hydrogen to from ammonia, what is the total number of molecules present after the reaction goes to completion?
I tried to solve it..can someone verify if 50 total molecule is the correct answer?
The equation shows you that 1 molecule of nitrogen reacts with 3 molecules of hydrogen to produce 2 molecules of ammonia.
If you have 30 molecules of hydrogen, 10 molecules of nitrogen will react with it to produce 20 molecules of ammonia. Thus after the reaction has gone to completion there will be 20 molecules of ammonia PLUS 10 molecules of unreacted nitrogen giving a total of 40 molecules.
OOPS I can't add 10+20=30!
sorry!
To determine the total number of molecules present after the reaction goes to completion, we first need to calculate the number of molecules of ammonia (NH3) produced.
The balanced chemical equation gives us the stoichiometry of the reaction, meaning the ratio of reactants and products. According to the equation, 1 molecule of nitrogen (N2) reacts with 3 molecules of hydrogen (H2) to produce 2 molecules of ammonia (NH3).
From the given information, we know that there are 20 molecules of nitrogen and 30 molecules of hydrogen. To determine the limiting reactant, we need to compare the number of moles of each reactant.
Moles of nitrogen = number of nitrogen molecules / Avogadro's number
= 20 / 6.022 × 10^23 (molecules/mol)
= 3.32 × 10^-23 mol
Moles of hydrogen = number of hydrogen molecules / Avogadro's number
= 30 / 6.022 × 10^23 (molecules/mol)
= 4.98 × 10^-23 mol
Next, we compare the moles of nitrogen and hydrogen to find the limiting reactant. In this case, nitrogen is the limiting reactant since it has fewer moles.
Using the stoichiometry of the reaction, we can calculate the moles of ammonia produced. As stated in the balanced equation, 1 mole of nitrogen reacts to form 2 moles of ammonia.
Moles of ammonia = Moles of nitrogen × (2 moles of ammonia / 1 mole of nitrogen)
= 3.32 × 10^-23 mol × (2/1)
= 6.64 × 10^-23 mol
Finally, to find the total number of molecules present after the reaction goes to completion, we add up the molecules of each species.
Number of molecules of nitrogen = Moles of nitrogen × Avogadro's number
= 3.32 × 10^-23 mol × 6.022 × 10^23 (molecules/mol)
= 2 × 10^1 molecules
Number of molecules of hydrogen = Moles of hydrogen × Avogadro's number
= 4.98 × 10^-23 mol × 6.022 × 10^23 (molecules/mol)
= 3 × 10^1 molecules
Number of molecules of ammonia = Moles of ammonia × Avogadro's number
= 6.64 × 10^-23 mol × 6.022 × 10^23 (molecules/mol)
= 4 × 10^1 molecules
Therefore, after the reaction goes to completion, the total number of molecules present would be 20 molecules of nitrogen, 30 molecules of hydrogen, and 40 molecules of ammonia.