calculus
posted by Frank .
Find an equation of the tangent line to the curve at the given point.
y = 3x^2  x^3, (1,2)

Calculate the slope m by taking the derivative and evaluating it at x = 1
dy/dx = 6x  3x^2 = 3 at x = 1
The equation for the tangent line will be
(y2)/(x1) = m = 3
Write it out in y = mx + b form.
y  2 = 3x  3
y = 3x  1
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