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Math another problem

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Solve 1/C=1/C1+1/C2 for C1.

  • Math another problem -

    Subtract 1/C2 from each side.

    1/C1 = 1/C - 1/C2 = (C2-C)/(C*C2)

    Now turn both fractions upside down. This is called "taking the reciprocal of both sides"

    C1 = C*C2/(C2 - C) = 1/[(1/C) - (1/C2)]

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