Calc
posted by mike .
What is the derivative of 4^[sin(pi*x)]? And how do you go about solving it? thanks

Calc 
Count Iblis
4^[sin(pi*x)] =
exp[log(4) sin(pi x)]
So, by the chain rule, the derivative is:
exp[log(4) sin(pi x)] log(4) pi
cos(pi x) =
pi log(4) 4^[sin(pi x)] cos(pi x)
Respond to this Question
Similar Questions

Calc
Find the derivative of a) y=cos (x/2) b) yx3x^2 +6 = y^4 + x a) sin (x/2)(2+x)/2^2 sin(x/2)(x/2) b) x dy/dx + y  6x = 4y^3 dy/dx + 3x^2 dy/dx (x 4 y^3) = 3x^2 y +6x dy/dx = (3x^2 y +6x)/(x 4 y^3) I used inplicit differation … 
calc
i did this problem and it isn't working out, so i think i'm either making a dumb mistake or misunderstanding what it's asking. A particle moves along the x axis so that its velocity at any time t greater than or equal to 0 is given … 
calculus
Could someone check my reasoning? thanx Find the derivative of the function. sin(sin[sinx]) I need to use the chain rule to solve. So I take the derivative sin(sin[sinx) first. Then multiply that by the inside which is the derivative 
AP CALC
derivative of y= x^2 sin x 
calc a
derivative of; ((1+x^2)^2)sin(2x) 
Calculus 12th grade (double check my work please)
1.)Find dy/dx when y= Ln (sinh 2x) my answer >> 2coth 2x. 2.)Find dy/dx when sinh 3y=cos 2x A.2 sin 2x B.2 sin 2x / sinh 3y C.2/3tan (2x/3y) D.2sin2x / 3 cosh 3yz...>> my answer. 2).Find the derivative of y=cos(x^2) … 
AP Calc
How do you find the derivative of y=sin(x)*(sinx+cosx) 
Calc
find the derivative f(x)= e^3x x sin(4x) 
Derivative
Can you help me find the derivative of y= cos(x)/1+sin(x).. the / is a fraction bar. I have a hard time finding trig derivatives because I don't really know what the derivative of cos,sin ,or tan would be honestly. 
Math  Calc/Algebra/Trig
I'm trying to find all the points on the graph y=4/3cos^3xcosx where the tangent line is horizontal. I took the derivative, which gave me: 4cos^2(x)sin(x)+sin(x) Now I need to solve it for x and I'm not sure how. Can you help?