algebra
posted by Anonymous .
The base of a triangle is 4cm greater than the height the area is 48cm^2 find the height and the length of the base

Let the height be x cm
so the base is x+4 cm
Area of triangle = (1/2)base x height
so 48 = (1/2)(x)(x+4)
96 = x^2 + 4x
x^2 + 4x  96 = 0
Can you solve this quadratic?
Hint: it factors quite nicely
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