posted by DELLI .
A car makes a trip due north for three fourths of the time and due south one-fourth of the time. The average northward velocity has a magnitude of 27m/s, and the average southward velocity has a magnitude of 17m/s. What is the average velocity, magnitude and direction of the displacem,ent vector
Assume t= 1 minute = 60 s.
From v = d/ t, equation for d will be v.t
Individually solve for d for north & south, you'll arrive at +1215 m for north displacement, and -255 m for south.
Add these values to get total displacement. Answer for d sub t = +960 m.
Thus the magnitude of displacement vector is 960 m, north direction (as indicated by the + sign).
Solving for average velocity, use total displacement divided by the total elapsed time:
+960m / 60 s = 16 m/s, direction is north (positive answer)