physics

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A pair of glasses are dropped from the top of a 32.0 m high stadium. A pen is dropped from the same position 2.00 s later. How long does it take for the glasses to hit the ground? How high above the ground is the pen when the glasses hit the ground? (Disregard air resistance)

  • physics -

    Find the time of fall by using:
    y = (1/2)gt^2
    (y is given and g = 9.8m/s^2, Solve for t)

    When the glasses hit the ground, the pen has been falling for (t-2.00s). The height above the ground of the glasses is:
    32.0m - (1/2)g(t-2)^2

  • physics -

    Correction to the previous answer:
    "The height above the ground of the glasses is:
    32.0m - (1/2)g(t-2)^2" should read:
    The height above the ground of the pen is:
    32.0m - (1/2)g(t-2)^2

  • physics -

    2 m

  • physics -

    25.6

  • physics -

    1.5 m

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