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A diver springs upward with an initial speed of 2.1 m/s from a 4.5 m board.
(a) Find the velocity with which he strikes the water. (Hint: When the diver reaches the water, his displacement is y = -4.5 m (measured from the board), assuming that the downward direction is chosen as the negative direction.)b. What is the highest point he reaches above the water?

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    (a) His kinetic energy will increase by M g H, where H = 4.5 m. Therefore
    V2^2 = V1^2 + 2 g H
    V1 = 2.1 m/s

    (b) The increase in height at the highest point, h, is the elevation at which the potential energy increases by (1/2)MV1^2

    2 g h = V1^2

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