Post a New Question


posted by .

Approximate the greatest real zero of the function g(x)= x^3-3x+1 to the nearest tenth.

I know that there is a zero between -2 and -1, and another between 0 and 1 but do not know how to find it to the nearest tenth. The only example shown in my book uses a calculator and mine does not have instructions for the same functions as the one in the book. I have checked for online calculators and cannot find one to do the calculations either.

Any help would be great as I have to get finished with math this week.


  • Pre-Calculus -

    Try solving it iteratively: if g(X)=0, then X^3-3X+1=0, so rearrange the equation to read

    X = (3X-1)^(1/3)

    Not put X = 2, and evaluate the function. You'll get about 1.71. Feed that into the equation again, and you'll get about 1.60. Keep going for a few more iterations until it settles down. Then try feeding it into the original equation and see if it works.

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question