Chemistry

posted by .

A solution is made by mixing 20.0 mL of toluene C6H5CH3d=0867gmL with 140.0 mL of benzene C6H6d=0874gmL. Assuming that the volumes add upon mixing, the molarity (M) and molality (m) of the toluene are...

______ M and

______ m.

I need help. :(

  • Chemistry -

    1. Use:
    mass = (volume)*(density), or
    grams = (milliliters)(grams/ml)
    to calculate the mass (grams) of each compound.
    2. Find the molar mass of toluene.
    3. Divide the mass (grams) of toluene by the molar mass of toluene to convert grams to moles.
    4. Convert the grams of benzene to kilograms.
    5. molality = (moles toluene)/(kgs of benzene)

  • Chemistry -

    To find the molarity,
    1. Convert the 140 mLs of benzene to liters
    2. Molarity = (moles of toluene) / (liters of benzene)

    NOTE: This is a continuation of the previous answer (finding the molality). Refer to steps 2 and 3.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Chemistry

    A solution is made by mixing 35.0 mL of toluene C6H5CH3 d=0867gmL with 125.0 mL of benzene C6H6 D=0874gmL. Assuming that the volumes add upon mixing, the molarity (M) and molality (m) of the toluene are?
  2. chemistry

    A solution is made by mixing 20.0 mL of toluene C6H5CH3d=0.867gmL with 150.0 mL of benzene C6H6d=0.874gmL. Assuming that the volumes add upon mixing, what are the molarity (M) and molality (m) of the toluene
  3. Chemistry

    A solution is made by mixing 20.0 mL of toluene C6H5CH3d=0867gmL with 140.0 mL of benzene C6H6d=0874gmL. Assuming that the volumes add upon mixing, the molarity (M) and molality (m) of the toluene are?
  4. chem

    A solution is made by mixing 20.0 mL of toluene C6H5CH3d=0867gmL with 150.0 mL of benzene C6H6d=0874gmL. Assuming that the volumes add upon mixing, the molarity (M) and molality (m) of the toluene are ____M and _____m.
  5. Chemistry

    A solution is made by mixing 35.0 mL of toluene C6H5CH3d=0867gmL with 125.0 mL of benzene C6H6d=0874gmL. Assuming that the volumes add upon mixing, the molarity (M) and molality (m) of the toluene are
  6. chemistry

    A solution is made by mixing 35.0 mL of toluene C6H5CH3d=0867gmL with 125.0 mL of benzene C6H6d=0874gmL. Assuming that the volumes add upon mixing, the molarity (M) and molality (m) of the toluene are how do you find the L of SOLUTION
  7. chemistry

    A solution is made by mixing 35.0 mL of toluene C6H5CH3d=0867gmL with 125.0 mL of benzene C6H6d=0874gmL. Assuming that the volumes add upon mixing, the molarity (M) and molality (m) of the toluene are so the L of solution is...?
  8. chemistry

    A solution is made by mixing 25.0 mL of toluene C6H5CH3d=0867gmL with 135.0 mL of benzene C6H6d=0874gmL. Assuming that the volumes add upon mixing, the molarity (M) and molality (m) of the toluene are ?
  9. chemistry

    can someone please help me with this? i've been stuck on this one forever... A solution is made by mixing 25.0 mL of toluene C6H5CH3d=0867gmL with 135.0 mL of benzene C6H6d=0874gmL. Assuming that the volumes add upon mixing, the molarity
  10. chemistry

    can someone help me with this please? i've been stuck on this one forever... A solution is made by mixing 25.0 mL of toluene C6H5CH3d=0867gmL with 135.0 mL of benzene C6H6d=0874gmL. Assuming that the volumes add upon mixing, the molarity

More Similar Questions