algebra
posted by larissa .
solve:
the square root of (x) +2= the square root of (5x) +3

x = 4 is the answer, if you take the positive square roots. There may be other answers if you take the negative square root on one or both sides.
I got that by trial and error, not by using algebra. The algebra got too messy. 
Whatever roots exist must be between x = 0 and 5, otherwise you get imaginary numbers. As I said in a previous post, x=4 is the answer is you take postive squate roots on both sides. x=1 is also an answer, if you take the positive root of 1 on the left and the negative root of 4 on the right.

Here is the algebraic proof:
sqrt(x) + 2 = sqrt(5x) + 3
sqrt(x) 1 = sqrt(5x)
2x = 2 sqrt(x) +4
x = sqrt(x) + 2
Let sqrt(x) = y, and you have a quadratic equation:
y^2 y +2 = (y2)(y+1) = 0
y = 2 or 1
x = y^2 = 4 or 1
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