Help with Math

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How would i determine the values of 'k' if the graph y=2x^2-2x+3k intersects the x-axis at two distinct points?

  • Help with Math -

    This is similar ot the other problem.

    If the equation crosses the x-axis then y=0.

    So you need to find the solutions for

    0=2x^2-2x+3k

    using the general equation we get

    x=-2+/-(4-4.2.3k)^.5/4

    for there to be real values

    4-24k>0 (we can't square root a number less than zero, and it can't equal zero as the question says there are two distinct points. Zero would give us two coincident points)

    so 4>24k or k<4/24 k<0.1667

    Check my working!

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