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Show that when pH = pKa, the maximum buffer capacity (at 298.15 K) is given by: âmax = 0.576C
where C is the total concentration of conjugate acid and conjugate base. The first two terms in the brackets on the right hand side of equation (8.5) can be neglected. B( KaCH/(Ka +H)^2 x ln 10

  • CHEM -

    Have you posted everything in your problem? And what is a (with ^ over it) max?

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