x=3y-4
2x-y=7
solve as a set/substitution.
Substitute 3y - 4 for x in the second equation and then solve it for y.
6y - 8 - y = 7
5y = 15
y = ?
Then use either equation to solve for x.
thank you
drwls!!!!!!!!!!!!!
To solve this system of equations using the substitution method, we will begin by solving one of the equations for one variable and then substituting that expression into the other equation.
Let's start with the first equation:
x = 3y - 4 (Equation 1)
We need to solve this equation for x. To do that, we isolate x:
x + 4 = 3y
x = 3y - 4 (Equation 2)
Now we substitute Equation 2 (x = 3y - 4) into the second equation (2x - y = 7):
2(3y - 4) - y = 7
6y - 8 - y = 7
5y - 8 = 7
5y = 7 + 8
5y = 15
y = 15/5
y = 3
Now that we have found the value of y, we can substitute it back into Equation 2 to find the value of x:
x = 3(3) - 4
x = 9 - 4
x = 5
Therefore, the solution to the given system of equations is x = 5 and y = 3.