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A small sperical insulator of mass 8.00X10^-2 kg and charge +0.600 mC is hung by a thin wire of negligible mass. A charge of -0.900 mC is held 0.150 m away from the spere and directly to the right of it, so the wire makes an angle [theta] with the vertical. Find (a) the angle [theta] and (b) the tension in the wire.

  • physics -

    Let T be the tension in the wire.
    A vertical force balance of the insulator says:
    T sin theta = M g
    A horizontal force balance says :
    T cos theta = k Q1*Q2/R^2
    which is Coulomb's law. k is the Coulomb constant and Q1 and Q2 are the two charges.
    Solve the two equations in the two unknowns, theta and T.

    Hint: divide one equation by the other to get tan theta and eliminiate T.

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