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posted by Katie Monday, June 9, 2008 at 5:58pm.

solve 2sin^2x+sinx-1=0 in the interval [0, 2pi0

Call sin a new variable y and solve the quadratic equation for y: 2y^2 +y -1 = 0 (2y - 1) (y + 1) = 0 y = sin x = -1/2 or -1

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