Calculus again
posted by Sam .
Find the equation of the tangent to y=2xe^x at the point where x=0
So I found the first derivative by doing the sum rule and product rule.
I got e^(x)(x1)
Then I found the slope by substituting 0 for x and got 1.
Then I found y by substituting 0 into the original equation and got 2.
So for my final equation after finding b I had y=1x+2
But in the back of the book the answer says x+y2=0.

You can simplify things right from the start by writing the equation for the tangent as:
Delta Y/DeltaX = y'
The derivative y' is to be evaluated at the point where you take the tangent, Delta Y and Delta x are the differences in the y and x coordinate relative to the values they take at the point where the tangent touches the graph of the function.
Respond to this Question
Similar Questions

got a couple of calculus questions
1. What is the equation of the tangent line to y = 2*x(x  4)^6 at point (5, 10)? 
Math, Calculus
Find the derivative of the function. y= xcosx  sinx What's the derivative? 
calculus
First I would find the first derivative which is the slope and then would I plug in the given value into the original equation to find y and then use yy_1=m(xx_1)? 
calculus
Alright so implicit differentiation is just not working out for me. Use implicit differentiation to find the slope of the tangent line to the curve at point (4,1). y / (x2y) = x^3 + 4 Tried quotient rule to get the derivative of the … 
calculus
Consider line segments which are tangent to a point on the right half (x>0) of the curve y = x^2 + 1 and connect the tangent point to the xaxis. If the tangent point is close to the yaxis, the line segment is long. If the tangent … 
CALCULUS
Use the product rule to calculate the derivative. dh dx x = 4 , h (x) = (x^(1/2) + 7x)(9  x^1) very weird.. i know how to do it, i used product rule and got an answer in decimal but the website is not accepting it. Can any one help … 
Applied Calculus
Find the first and second derivative of the function: x/(7x+10) Using quotient rule. This is part of my homework in the section named "Higher Order Derivatives". I am confused on getting the second derivative, as I found the first … 
Calculus derivative
find the slope m and an equation of the tangent line to the graph of the function f at the specified point. original: x^2/x+10 point: (3,9/13) After I found the derivative: (x+10)(2x)(x^2)(1)/((x+10))^2 How do I get the slope? 
Calc I
if f(t)=sqrt(4t+1) find f''(2) I got the first derivative to be: 1/2(4t1)^1/2 * 4t^3 and i'm trying to figure out if i need the product rule again to find the second derivative 1t^3(4t1)^3/2 * 4t^3 The answer if 4/27 and I'm … 
Math
Find the equation of the line tangent to curve x=sec(t), y=tan(t), at t=pi/6. I found th slope(derivative of the two which was csc(t). Plugged in Pi/6 and got 2 as the slope. Now how do I find the equation of the tangent?