posted by Anonymous .
One method for reclaiming silver metal from silver chloride results in a 94.6%
yield. Calculate the actual mass of silver that can be produced in this reaction
if 100.0 g of silver chloride is converted to silver metal.
2AgCl(s) y 2Ag(s) . Cl2(g)
Write the equation which you have BUT you have omitted the yield sign and and + signs. No way to know the difference between reactants and products.
Convert 100.0 g AgCl to mols.
Using the coefficients in the balanced equation, convert mols AgCl to mols Ag.
Convert mols Ag to grams Ag by grams = mols x molar mass.
Substitute in the earlier problem for the percent yield and solve for the actual amount. Post your work if you get stuck.
2AgCl(s) y 2Ag(s) 1 Cl2(g)