Post a New Question

Algebra 2

posted by .

Which quadratic function has its vertex at (2,3) and passes through (1,0)?
a. y = 2(x-2)^2+3
b. y = -3(x-2)^2+3
c. y = -3(x+2)^2+3
d. y = 2(x-2)^2-3

Could you explain why you got your answer, too?

  • Algebra 2 -

    if y = a(x-p)^2 + q then the vertex is (p,q)

    both a) and b) match that pattern
    but which one does (1,0) satisfy?

    substitute to find out.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. algebra

    1)Find the exact solutions to 3x^2=5x-1 using the quadratic formula. answer=5 plus or minus the square root of 37 over 6 2)Use the discriminant to determine the number and type of roots for the equation 2x^2-7x+9=0 answer=2 complex …
  2. math

    A quadratic function has its vertex at the point (-9,3). The function passes through the point (2,-1). Find the quadratic and linear coefficients and the constant term of the function.
  3. Math

    Find the quadratic function that has the indicated vertex and whose graph passes through the given point. Vertex: (2,3) Point: (0,2) I do not know how to do this! Please explain!! Thank You
  4. Math

    Find the quadratic function that has the indicated vertex and whose graph passes through the given point. Vertex: (2,3) Point: (0,2) I do not know how to do this! Please explain!! Thank You
  5. college algebra

    determine the quadratic function f whose vertex is (2,-4) and passes through (3,-1) f(x)= what?
  6. Algebra

    Determine the quadratic function of f whose vertex is (2,-1) and passes through (3,1) f(x)=
  7. algebra

    Determine the quadratic function f whose vertex is (3,-2) and passes through(1,6) f(x) = ax^2 + bx + c
  8. College Algebra

    The graph of a quadratic function f(x) is shown above. It has a vertex at (-2,4) and passes the point (0,2). Find the quadratic function y=a(x-(-2))^2+4 y=a(x+2)+4 2=a(x+2)+4 -4 -4 -2=a(0+2)/2 -1+ a function -1(x+2)+4 ?
  9. College Algebra

    A quadratic function has its vertex at the point (-9,8). The function passes through the point (9,4). When written in vertex form, the function is f(x)= a(x-h)^2 +k, where a) h)-9 k)8 4=a(9)^2+8 4=a(9+9)^2+8 4=a(18)^2+8 4=a(332) a=0.01204 …
  10. Pre-Calc

    A quadratic function has its vertex at the point (-5,-2). The function passes through the point (-8,-10). Find the quadratic and linear coefficients and the constant term of the function.

More Similar Questions

Post a New Question