Intermediate algebra
posted by Rene .
Seven times the difference of six and a twice a number yields the same result as the same number decreased by one.

7(62x) = x 1
42  14 x = x 1
15 x = 43
x = 43/15 
Combine like terms:
3x2 + 2x – 4x2 – 9 + 6x – 2x2 + 8 
Solve for x:
2(x – 5) + 7 = x – 8 – 5x 
Solve for x:
(x – 2)/5 – 3/2 = (x + 1)/10 
How do you Solve for x:
(x – 2)/5 – 3/2 = (x + 1)/10 
7(62n)=n1

The difference of a number and 9 is the same as 45 decreased by that same number.
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