# Calculus

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Let f(x) = sqrt(3x+15)

Find f'(x)

Can anyone who does this please explain step by step why you did what you did? I have a lot of difficulty finding the derivative with radicals.

• Calculus -

f(x)=(3x + 15)^(1/2)
f'(x)=(1/2)((3x+15)^(1/2 - 1)) 3
f'(x)=(3/2)(3x+15)^(-1/2)

f'(x)=3/(2*(3x+15)^(1/2))

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