math
posted by doug .
determine vertex, focus and directrix of parabola. then graph the parabola.
first equation:
y^2 2x8=0
second equation:
y^2 4y 12x= 8

We can't draw graphs for you here. I sugggest you do that yourself
Rewrite them in the form
x = a(yb)^2 + c
When you have done that, the vertex will be at x=c, y=b. The focus will be located at y=b, x = c + p, and the directrix will be the line x = c  p
The value of p is
p = 1/(4a)
For your first equation,
x = y^2/2 4
so a = 1/2, b = 0 and c = 4
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