MathGeometry
posted by Megan .
The material for the base of a box will cost three times as much as the material for the sides and top of the box. The box must have a volume of 200m cubed. Find the most efficient way to built this box.

There is additional information needed.
I am guessing from previous questions like this that the base is a square.
Let the base be x metres by x metres, an let the height be y metres.
then (x^2)y = 200 and y = 200/x^2
Cost = 3(x^2) + 1(4xy + x^2)
= 4x^2 + 4xy
= 4x^2 + 4x(200/x^2)
= 4x^2 + 800/x
Cost' = 8x  800/x^2 = 0 for a max/min of Cost
8x = 800/x^2
x^3 = 100
x = 100^(1/3) = 4.64 m
then y = 200/4.64^2 = 9.28 m
the box should have a base of 4.64m by 4.64m and a height of 9.28 m
I also have a feeling that the volume was given as 2000, then the answer would have been exactly x=10 and y = 20
which would be in the same height:base length of 2:1
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