Calculus

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I am having a lot of trouble doing these types of problems. Can someone show me how to do this. Thank you for your time.

Evaluate the definite integral

4
x(x+3)dx
0

  • Calculus -

    expand it first to get

    ⌠ (x^2 + 3x)dx from 0 to 4


    = (x^3)/3 + (3/2)x from 0 to 4
    = 64/3 + 6 - 0
    = 82/3

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