Pre Calculus
posted by Josh .
Can someone help me with this problem...I have no Idea how to do it.
Find the area between each curve and the xaxis for the given interval.
y=16xx^3 from x=0 to x=4
Thanks for the help>>

A quick analysis and sketch of the curve will show xintercepts at 4,0, and 4
Since you want the area from 0 to 4, it will be the region above the xaxis.
area =
⌠ 16x  x^3 dx from 0 to 4
⌡
= [8x^2  1/4x^4] from 0 to 4
= (8(16)  1/4(256))  0
= 12864
= 64
I find your statement "..I have no Idea how to do it" rather puzzling. This is a routine and quite simple problem in this topic, if you are studying Calculus
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