posted by Andy .
I tried doing this problem, but I have no idea how to do it, can someone show me how to get it done. Thanks.
Evaluate the indefinate integral
Add the separate integrals of the two terms.
The integral of x^4 dx is x^5/5.
The integral of -6 x dx is -6*(1/2)x^2 = -3x^2.
Add an arbitrary constant C to the sum.
(x^5)/5 - 3 x^2 + C
Wait, is that the answer
an would it be (x^5/5) or is the whole rest besides the C on the bottom.
The answer is the last line I wrote
I know, but I don't see what you mean
Is 5-3x^2 all under x^5
No. 3x^2 and C are separate additive terms. As I said in the beginning, you add the integrals of each term.
so, the answer would be like this