# More Calc

posted by .

Find the area between each curve and the x-axis for the given interval.

y=6x^2+5 from x=0 to x=5

Thanks.

• More Calc -

(6/3) x^3 + 5 x
at 5 - at 0

## Similar Questions

1. ### math

Find the area between each curve and the x axis for the given interval. y=16x-x^3 from x = 0 to x = 4 Thanks ahead of time.
2. ### Pre Calculus

Can someone help me with this problem...I have no Idea how to do it. Find the area between each curve and the x-axis for the given interval. y=16x-x^3 from x=0 to x=4 Thanks for the help>>
3. ### PRE calculus

Find the area between each curve and the x-axis for the given interval. y=6x^2+5 from x=0 to x=5 I'm just starting to learn about this and am very confused. Can someone show me how to do this. Thanks. I need help.
4. ### HELP WITH MATH

Sorry the caps lock was on. Can you help me with this pre calculus question. I'm not quite sure how to do this. Here are the instructions. Find the area between each curve and the x-axis for the given interval: y=2x^2+x+1 from x=3 …

Find the area between each curve and the x-axis for the given interval. 1)y = x^4 + 5 from x = 0 and x = 5 2)y = 3x^2 + 5x - 1 from x = 1 to x = 4 3)y = 4x - x^3 from x = 0 to x = 2
6. ### Pre Cal.

Find the area between each curve and the x-axis for the given interval. a. y=x^4+5 from x=0 to x=5 650 b. y=3x^2+5x-1 from x=1 to x=4 97.5 c. y=4x-x^3 from x=0 to x=2 4
7. ### calculus 1

find the total area between the curve ( y= 4-x to the second power) and the x-axis over the interval [-3,7]
8. ### Calculus

These are the two problems from my homework I don't get.. can you help me?
9. ### calculus(Lab)

Well, first graph the graph of f(x)=-1/10x^2 + 3 2. We are going to approximate the area between f and the x-axis from x = 0 to x = 4 using rectangles (the method of Riemann sums). This is not the entire area in the first quadrant, …
10. ### Calc

Use the limit process to find the area of the region between the graph of the function and the x-axis over the given interval. y = −4x + 6, [0, 1]

More Similar Questions