Precalc again
posted by John .
lim Square root of (x) 3 over x9
x>9
thanks.

Precalc again 
Damon
[x^.5 3] / (x9) is of course 0/0 so use
derivative of top/derivative of bottom
= [.5 x^.5 ] /1
= as x>9
[.5/3 ]/1
= .16666666666666.......
check
let x = 8.9
x^.5 3 = .0167
8.99 = .1
ratio = .167
let x = 8.99
x^.5  3 = .00167
8.99  9 = .01
ratio = .167
sure enough
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