# mathematics

posted by
**Donna**
.

If 3xy^3 - 4x = 10y^2, find y ' (x)

a) (4 + 3y^2)/(9xy^2 + 20y)

b) (4 - 3y^2)/(9xy^2 - 20y)

c) (3 + 4y^2)/(20xy^2 + 9y)

d) (3 - 4y^2)/(20xy^2 - 9y)

posted by
**Donna**
.

If 3xy^3 - 4x = 10y^2, find y ' (x)

a) (4 + 3y^2)/(9xy^2 + 20y)

b) (4 - 3y^2)/(9xy^2 - 20y)

c) (3 + 4y^2)/(20xy^2 + 9y)

d) (3 - 4y^2)/(20xy^2 - 9y)