# math

posted by .

tan/1-cot +cot/1-tan =1+sec cosec

• math -

The proper symbol used for cosecant is csc.

Is <1+sec cosec> supposed to represent
(1+ sec)*csc or , 1 + (sec*csc)> ?

You should also have used parentheses around (1-cot) and (1+tan) to avoid confusion.

It may help to change tan/(1-cot)to the equivalent 1/(cot-1), and change cot/(1-tan) to 1/(tan-1), and then rewrite the sum on the left with a common denominator.

• math -

Factor the trinomial
c^2+5c+6

## Similar Questions

1. ### I dont think drawing a picture will help me drwls

Which expression is equivalent to tan theta-sec theta/sin theta?
2. ### math

Prove the following identities: a) (cosec θ + cotθ)(cosecθ - cotθ) = cotθtanθ b) 2/(1 + sinθ) + 1/(1- sinθ) = (3sec^2)θ - tanθcosecθ I basically just have to prove Left HandSide …
3. ### math

how do I simplify these? 1. (Cot/1-tan) + (Tan/1-Cot) - Tan - Cot 2. (1+cos) (csc-cot)
4. ### Math - Trig

I'm trying to verify these trigonometric identities. 1. 1 / [sec(x) * tan(x)] = csc(x) - sin(x) 2. csc(x) - sin(x) = cos(x) * cot(x) 3. 1/tan(x) + 1/cot(x) = tan(x) + cot(x) 4. csc(-x)/sec(-x) = -cot(x)
5. ### Math - Trigonometry

Verify the following: 1. cos x/(1-sinx)= sec x + tan x 2. (tanx+1)^2=sec^2x + 2tan x 3. csc x = )cot x + tan x)/sec x 4. sin2x - cot x = -cotxcos2x
6. ### Trigonometry

Please review and tell me if i did something wrong. Find the following functions correct to five decimal places: a. sin 22degrees 43' b. cos 44degrees 56' c. sin 49degrees 17' d. tan 11degrees 37' e. sin 79degrees 23'30' f. cot 19degrees …
7. ### trigonometry repost

Reduce (csc^2 x - sec^2 X) to an expression containing only tan x. (is this correct?
8. ### TRIGONOMETRY *(MATHS)

Q.1 Prove the following identities:- (i) tan^3x/1+tan^2x + cot^3x/1+cot^2 = 1-2sin^x cos^x/sinx cosx (ii) (1+cotx+tanx)(sinx-cosx)/sec^3x-cosec^3x = sin^2xcos^2x.
9. ### TRIG..............

Q.1 Prove the following identities:- (i) tan^3x/1+tan^2x + cot^3x/1+cot^2 = 1-2sin^x cos^x/sinx cosx (ii) (1+cotx+tanx)(sinx-cosx)/sec^3x-cosec^3x = sin^2xcos^2x.
10. ### GENRAL MATHS

PROVE THAT (1+COT A+TAN A)(SIN A-COS A)=SEC A\COSEC A-COSEC A\SEC A

More Similar Questions