algebra problem
posted by Tim .
I need to find the equation of a parabola. I am not sure if this is the correct way or if I have the correct answer.
Vertex at origin, focus is at (0,3)
Equation of parabola
vertex (0,0) focus (0,3)
focus (h,k+p)
(0,0+3)
y=03
directrix y=3
a=(1/4)(p)
a=(1/4(3))=(1/12)
a=(1/12) h=0 k=0
y=(1/12)(x0)^2+0
my answer is: y=(1/12)(x^2)+0

V(0,0), F(0,3).
1/4a = 3, 4a = 1/3, a = 1/12.
Y = a(x0)^2 + 0.
Y = (1/12)x^2.
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