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Find the standard form of the equation of the line that is perpendicular to -6x+5y=-6 and contains (8, -6)

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    By the way, thanks so much to anyone that can help me! (I forgot to add that before!)

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    The slope of the line
    -6x+5y=-6
    can be seen by rewriting it as
    y = (6/5)x - 6/5
    That slope is 6/5. A perpendicular line will therefore have slope -5/6.

    Such a line passing through (8, -6) would have the equation
    y +6 = (-5/6) (x-8)
    y = -6 -(5/6)x + 40/6
    y = (-5/6)x + (2/3)

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