# algebra1

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Colin invested \$32,000, part at 8% and part at 12%. If the total interest at the end of the year is \$3,160, how much did he invest at each rate?

• algebra1 -

X = amount invested at 0.08.
32000-X = amount invested at 0.12.

X(0.08) + (32000-x)(0.12) = 3160
Solve for x and 32000-x.
Check my thinking. Check my work.

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