algebra1

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Colin invested $32,000, part at 8% and part at 12%. If the total interest at the end of the year is $3,160, how much did he invest at each rate?

  • algebra1 -

    X = amount invested at 0.08.
    32000-X = amount invested at 0.12.

    X(0.08) + (32000-x)(0.12) = 3160
    Solve for x and 32000-x.
    Check my thinking. Check my work.

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